A NOTE ON THE YAMABE PROBLEM

Wang Xujia
Centre for Mathematics and its Applications, Australian National University, Canberra ACT 0200, Australia; Nankai Institute of Mathematics, Nankai University, Tianjin 300071, China

文章主题:凸函数 超曲面方程 Weingarten曲率 不等式

文章内容：...18(2005),322—326@01.18.4冲'(,,0200,;,,300071,)(.@...)(1.20,2005)'..1"1()&;(").(),,,一.;,.20003560,5345.0175.29.0175.25.(,),,3.=9[]==4/(一)9).口=:一△+一24(—1."='.()=,,()∈【90(1).(9)=//"一)/,(,).[1—3】,[4】.()&;(").一&;.4323(2)[1]6,【4].【1,4]51.(2)((11)).(6】,.0∈,,5:71,,(0):0,(0)=0△(0)=一(),()三10()0.(4),【8,9].159[7].0,0."1()70,=(一2)～15(5)00,一1～.1(5】..()=枷+&;()(=(一)(—,()4一(6),=0≤62,4;(0)≠0.([5]1[10]..=0(7)..()=(￡.(4),,￡2+2一2)下,.-=(一2)"～,,,,324'01.180&;0.正()=0()(一"+),2,上(),0一,=孚(1+2)一号(10).5(2+)0.,=(一2)5+2)(一2)(8.))(8.上[=,,(11)()&;0.-=,∈,,,一_2),5-1_÷0,0.￡=(),5-1—0.(7)≥一5,_..0.=(),(2).2=41(-2)<>,(9)&;(一2)[厂9.]/..(11),==&;㈤.,2/(一如"'～正￡=正+￡(正一正).()=(—正),,=:一2乎乎==【一2)[.芦]一下--'2..口(一):一正0,_÷00_÷0.—口(12)(13)(14)()(15).4325.()≤00.(13)爰(￡)0,,(—)0..,=,(12)(()=0),≥..岳(￡)0.(2).,口叫=(【叫=6,200(3),,(0))=,+口(+叫)正+正50,,(正+—正)1.-1=070,(16);(,"+).∑(兄,+)&;01.'/2'/2+0(12)(8).,0.()20..=一.,2,-1=.=0,&;0(七=1,2).&;0,-÷0-÷0,叫,(())(1+),()∈./4,1,,(17),/()-..(17)-.=1,=/0,7,()=()/.西,1,(-÷0)?'=2,=,()=()一(可),(,￡一(可)))1()=∑.口,(17)2,,口叫=2=00.-(17)(../()),1.(17),)0/4/-÷0.=,西()=叫(),=(2一+1)一.西2口=,=:0().』∑,=,<>』,=1+0(1)-÷0(1(4)).2,-÷..,西2'().,,.2-÷.,由2<>..一0),..=1,.(17)..(15)(17),(,)=(,<>7)(1+0(1))&;0(,&;0).'//)=∑,,2=∑(;,+)2(3)0,(1)&;0(2)&;0.=+2,()=(1)+(2)&;0.3261.18%()=()'..(8),()=/%=(一2)/2.,.,.[2/(-2)(,一2)/:(一2)[(2),(13)&;∞,(18)(19)(20).(20)(4).(2).(4),=1+(7''),[5].,,上+≥上+,(上)()一』.上+/'一&;0￡.2004.....[1】.66...1.,1976,55:269-296.